Unit Circle, important angles

Supplementary angles

It has been said that supplementary angles have their sum \pi\; or\; 180^\circ

Looking at the following figure, we can see that \triangle AEB' \cong \triangle ADC_1 by the AAS postulate.

\angle EAB' =\angle DAC_1

The actual angle is \pi-\beta

\sin (\pi-\beta)=DC_1

However, by CPCTC, DC_1=EB'=\sin \beta

We also notice that \cos (\pi-\beta)=AD=-AE=-cos \beta by CPCTC

This shows that:

\sin (\pi-\alpha)=\sin \alpha

\cos (\pi-\alpha)=-\cos \alpha

To avoid repetition we know that  \pi-\alpha=\frac{\pi}{2}+(\frac{\pi}{2}-\alpha)

This opens up the following:

\sin (\frac{\pi}{2}+\alpha)=\cos \alpha

\cos (\frac{\pi}{2}+\alpha)=-\sin \alpha

 

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